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幫助中心 > 技術(shù)知識庫 > 數據庫 > 數據庫管理 > Linux連接mysql報錯：Access denied for user ‘root’@‘localhost’(using password: YES)的解決方法

Linux連接mysql報錯：Access denied for user ‘root’@‘localhost’(using password: YES)的解決方法

2019-09-04 09:25:26 352

最近在linux連接mysql /usr/local/mysql/bin/mysql -uroot -p

輸入密碼出現Access denied for user 'root'@'localhost'(using password: YES)錯誤。下面話(huà)不多說(shuō)了，來(lái)一起看看詳細的解決方法吧

解決辦法：

1.先停止mysql 服務(wù)

service mysqld stop

2.進(jìn)入mysql安裝目錄bin/ 使用safe模式，進(jìn)行重啟：

./mysqld_safe --skip-grant-tables

3.使用root賬戶(hù)，無(wú)密碼登錄，修改root用戶(hù)密碼

mysql -u root

use mysql

update user set password=PASSWORD("你的密碼") where User = 'root';

4.重啟mysql，正常登錄

service mysqld restart 重啟

/usr/local/mysql/bin/mysql -uroot -p 然后輸入剛才重置的密碼

完成，連接成功！

提交成功！非常感謝您的反饋，我們會(huì )繼續努力做到更好！

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    <div   id="i8x8habwlx"   class="account-login">
      <h1 class="cloumn">會(huì )員登錄<a onclick="closeAll()"><i ></i></a></h1>
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			$('.solved-info').css('display','none');
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});

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	layui.use('rate', function(){
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		var ins1 = rate.render({
			elem: '#star'  //綁定元素
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					,'3': '中等'
					,'4': '好'
					,'5': 'very good'
				};
				this.span.text(arrs[value] || ( value + "星"));
			}
			,choose: function(value){
				$("input[name='star']").val(value);
				console.log(star)
				// feedback(3);
			}
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// type   0:提交反饋  1：有幫助  2：小心心
	function feedback(type=0) {
		var url = $("#url").val();
		var islogin = true;
		var post = $("#dataForm").serialize();

LD.ajax.post(url, post, function (data) {
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				console.log("未登錄");
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				$('#submit-success').show();
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</div>




















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